see arXiv:nucl-ex/0307010v1 (eq.16) or

arXiv:hep-ph/9612336v1

(1/mt**2)*dN/dmt = A * integral{ r* K_1(mt*cosh(rho)/T) * I_0(pt*sinh(rho)/T) dr }, integral over r=(0,1)

rho = 1/tanh(beta), beta = beta_max*r;

3 parameters: A, beta_max (blast or b) and T (slope)

First again check of the formula on the "ideal" PLUTO distribution for 1 GeV with T=58 MeV and b=0 (and A_2=0) - upper plots and the same with T=58 MeV and b=0.3 - lower plots :

The fits do not reproduce the input parameter to PLUTO - inverse slope and blast. Only in the 1st case b=0 is reproduced correctly, but also in this case the inverse slope differs from the original value (fitted 64 vs input 58 MeV). The PLUTO m_t spectrum shape (upper left) is pure exponential, when fitted by expo, it gives correct result T=58. Moreover the fitting function used here does not give exponential function for case b=0. Do I have a bug in the function?

- PLUTO up: T=58MeV, b=0 down: T=58, b=0.3 left: fit right: chi2contour plot b vs T:

- C+C 1 AGeV:

- C+C 2 AGeV:

- pi+:

- pi-:

I | Attachment | Action | Size | Date | Who | Comment |
---|---|---|---|---|---|---|

gif | c1c_mtfit_blast_exp.gif | manage | 68.7 K | 28 May 2008 - 12:59 | PavelTlusty | C+C 1 AGeV |

gif | c1c_pluto_mtfit_blast.gif | manage | 54.6 K | 28 May 2008 - 12:38 | PavelTlusty | PLUTO up: T=58MeV, b=0 down: T=58, b=0.3 left: fit right: chi2contour plot b vs T |

gif | c2c_mtfit_blast_exp.gif | manage | 61.5 K | 28 May 2008 - 13:01 | PavelTlusty | C+C 2 AGeV |

gif | c2c_mtfit_pim_exp_contour1.gif | manage | 5.6 K | 28 May 2008 - 13:10 | PavelTlusty | pi- |

gif | c2c_mtfit_pip_exp_contour1.gif | manage | 5.6 K | 28 May 2008 - 13:08 | PavelTlusty | pi+ |

This topic: Homepages > C <span class=<span class='foswikiSeparator'> > MtBlast

Topic revision: 28 May 2008, PavelTlusty

Topic revision: 28 May 2008, PavelTlusty

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