Conversion:

Equations to convert from a Mdc Segment given in the coordinates: z, ρ, θ, φ to a straight equation.

%DRAWING{"yz"}% %DRAWING{"xy"}%

%$ g: \vec{x} = \vec{r} + \lambda \cdot \vec{\alpha} $%, %$ \vec{r} = \left( \[ \begin{array}{c} \rho\cdot\cos(\phi) \\ \rho\cdot\sin(\phi) \\ z \end{array} \] \right)$%, %$ \vec{\alpha} = \left( \[ \begin{array}{c} \sin(\theta)\cdot\cos(\phi) \\ \sin(\theta)\cdot\sin(\phi) \\ \cos(\theta) \end{array} \] \right)$%

%$ g: \vec{x} = \left( \[ \begin{array}{c} \rho\cdot\cos(\phi) \\ \rho\cdot\sin(\phi) \\ z \end{array} \] \right) + \lambda \cdot \vec{\alpha} = \left( \[ \begin{array}{c} \sin(\theta)\cdot\cos(\phi) \\ \sin(\theta)\cdot\sin(\phi) \\ \cos(\theta) \end{array} \] \right) $%

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Last change by PeterZumbruch